logaritmiskandClaude Opus 5 83bdb84152 fix!: collapse a drift too small to represent, on a relative threshold
`time_expanded_joint` collapsed consecutive appearances only at
`drift <= 0.0` exactly. Anything smaller-but-positive got an explicit
`1.0 / drift` precision, which the matrix cannot hold: at `drift = 1e-16`
the entry is `1e16`, and `1e16 + 0.28` rounds back to `1e16`, so the
prior and the event contrasts are annihilated in the stored f64 before
the factorisation ever runs.

Measured, 8 competitors over 15 slices:

  drift_scale   before                      after
  1e-6          1.3e-3 relative error       exact
  1e-7..1e-9    Err(JointUnavailable)       exact
  1e-10         12 200x TOO SMALL, as Ok    exact

At 1e-10 the caller was handed sigma = 0.0055 where the truth is 0.6108
— a 111x overconfident interval, returned as a success.

This is representation, not conditioning. Solved in 200-digit precision
the same system converges smoothly onto the collapsed value and is flat
from 1e-16 to 1e-40, so the quantity is perfectly well conditioned. That
also rules out the obvious fix: symmetric (Jacobi) equilibration measured
30x WORSE, because the information is gone from the assembled matrix
before any solver sees it. The fix has to be at assembly.

The threshold balances the two errors that trade off. Ignoring a real
drift costs about `drift / V`; representing one costs about
`EPSILON * V / drift`. They cross at `V * sqrt(EPSILON)`, scaled to each
competitor's own prior variance.

Ordinary drift is far above it and unaffected — the default gamma
accumulates 0.0069 per unit time against a threshold of 1.0e-6 — and the
test asserts both halves: everything below the threshold reaches the
collapsed answer bit-identically, and a drift of 1e-2 still moves it, so
the test cannot pass by collapsing everything.

Also corrects the `JointUnavailable` message, which asserted "a
competitor has neither a proper prior nor any evidence" for a fixture
where every competitor had both.

BREAKING CHANGE: a drift variance below `prior_variance * sqrt(EPSILON)`
now collapses two appearances into one latent variable. Affected fits
previously returned a badly wrong variance or an error.

Closes #57

Co-Authored-By: Claude Opus 5 (1M context) <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_011hcFjNDmHXZF8URGLku5zZ
2026-09-09 17:03:00 +02:00

TrueSkill - Through Time

Rust port of TrueSkillThroughTime.py.

Other implementations

Drift

Skill drift models how a competitor's true skill can change between appearances. Each time they reappear after a gap, their skill uncertainty is widened by the drift model before the new evidence is incorporated.

Drift is represented by the Drift trait (src/drift.rs), generic over the history's time type:

pub trait Drift<T: Time>: Copy + Debug + Send + Sync {
    fn variance_delta(&self, from: &T, to: &T) -> f64;
    fn variance_for_elapsed(&self, elapsed: i64) -> f64;
}

Both methods return the amount to add to σ², not to σ. variance_delta works from two timestamps; variance_for_elapsed takes an already-computed elapsed count, and is used on the paths that cache it. Gaussian::forget applies the result entirely in variance space — from_mv(mu, variance() + variance_delta) — taking no square root.

That block is a quotation rather than a doctest. The custom-drift example below is compiled by CI, so it is what actually pins the signature.

ConstantDrift

The built-in ConstantDrift implements a linear random walk — skill uncertainty grows proportionally to time:

variance_delta = elapsed * γ²

This is the standard TrueSkill Through Time model. Pass a ConstantDrift(gamma) when constructing a Rating:

use trueskill_tt::{ConstantDrift, Gaussian, Rating};

// gamma = 0.1 means skill can shift ~0.1 per time unit.
let rating: Rating<i64, ConstantDrift> =
    Rating::new(Gaussian::from_ms(0.0, 6.0), 1.0, ConstantDrift(0.1));

assert_eq!(rating.drift().0, 0.1);

The type annotation is load-bearing: ConstantDrift implements Drift<T> for every T: Time, so without it T is ambiguous.

Custom drift

Implement Drift<T> to express any other model. For example, a drift that saturates after a long absence, with uncertainty growing as the square root of elapsed time instead of linearly:

use trueskill_tt::{Drift, Gaussian, History, Rating, Time};

#[derive(Clone, Copy, Debug)]
struct SqrtDrift {
    gamma: f64,
}

impl<T: Time> Drift<T> for SqrtDrift {
    fn variance_delta(&self, from: &T, to: &T) -> f64 {
        let elapsed = from.elapsed_to(to).max(0) as f64;
        elapsed.sqrt() * self.gamma * self.gamma
    }

    fn variance_for_elapsed(&self, elapsed: i64) -> f64 {
        (elapsed.max(0) as f64).sqrt() * self.gamma * self.gamma
    }
}

// On a single Rating:
let rating: Rating<i64, SqrtDrift> =
    Rating::new(Gaussian::from_ms(0.0, 6.0), 1.0, SqrtDrift { gamma: 0.5 });

// Or for a whole History, via the builder:
let history = History::builder().drift(SqrtDrift { gamma: 0.5 }).build();

assert_eq!(rating.beta(), 1.0);
assert_eq!(history.log_evidence(), 0.0);

HistoryBuilder::drift is the only way to set a history's drift model; there is no gamma() shorthand. The default is ConstantDrift(GAMMA).

Per-competitor drift

A History has one drift model, but individual competitors can scale it. Member::with_drift_scale(s) multiplies the drift variance that competitor accumulates, so s is in the same units as gamma: ConstantDrift(g) at scale s behaves exactly as ConstantDrift(g * s) would, for that competitor alone.

0.0 pins a competitor still. That is what makes a fixed reference point expressible in the same graph as moving competitors — a bot at a known strength, a rating floor, a course difficulty:

use trueskill_tt::{ConstantDrift, Event, History, Member, Outcome, Team};

let mut h = History::builder().drift(ConstantDrift(0.1)).build();

h.add_events(vec![Event {
    time: 0,
    teams: [
        Team::with_members([Member::new("player")]),
        // A course does not improve. Pin it, and the round's evidence
        // lands on the player instead of being split between the two.
        Team::with_members([Member::new("layout_7").with_drift_scale(0.0)]),
    ]
    .into_iter()
    .collect(),
    outcome: Outcome::winner(0, 2),
}])
.unwrap();

h.converge().unwrap();

Like with_prior, the scale is competitor configuration, not a per-event value: it applies to the competitor for the whole history, and it applies whenever it is supplied — including on a key the history already knows. Configuring one late still refits the whole history rather than taking effect only from that event onward, because converge refits from competitor state. Repeating the same value is inert; supplying two different values for one competitor within a single batch is InferenceError::ConflictingCompetitorConfig, since events in a batch have no order. The scale must be finite and non-negative; ingestion otherwise fails with InferenceError::InvalidParameter.

The fluent EventBuilder reaches this too: .team([...]) is the common case and leaves both unset, while .members([...]) takes Member values directly, so h.event(t).members([Member::new("layout_7").with_drift_scale(0.0)]) is equivalent to the typed shape above.

Scored outcomes

Use Outcome::scores([...]) when you have continuous per-team scores rather than just ranks. Adjacent score margins flow into a MarginFactor that adds soft Gaussian evidence about the latent performance diff. Configure HistoryBuilder::score_sigma(σ) to control how much you trust the margins (smaller σ = more trust).

use trueskill_tt::History;

let mut h = History::builder().score_sigma(2.0).build();
h.event(1)
    .team(["alice"])
    .team(["bob"])
    .scores([21.0, 9.0])
    .commit()
    .unwrap();
h.converge().unwrap();

Prediction

predict_outcome gives the full distribution over finishing orders. Each entry is a rank vector in the same shape Outcome::ranking takes — equal ranks mean a tie — so an outcome feeds straight back into inference.

use trueskill_tt::History;

let mut h = History::builder().p_draw(0.1).build();
h.record_winner(&"alice", &"bob", 1).unwrap();
h.converge().unwrap();

let p = h.predict_outcome(&[&[&"alice"], &[&"bob"]]).unwrap();

// Probabilities are exhaustive and disjoint, so they sum to one.
assert!((p.total() - 1.0).abs() < 1e-6);

let (best, likelihood) = p.most_likely().unwrap();
println!("most likely: {best:?} at {likelihood:.3}");
println!("draw:        {:.3}", p.probability_of(&[0, 0]));

Supports any number of teams. Because the outcome space grows factorially, the full distribution is capped at MAX_PREDICTED_TEAMS; two cheaper entry points stay available at any size:

  • predict_win_probabilities(teams)P(team i finishes strictly first), quadratic in team count.
  • predict_ranking(teams, ranks) — one specific finishing order.

Unknown keys are an error by default, not a silent omission: a team the history has never seen cannot produce a confident-looking probability. The error names the key, and every key must already be known — pre-filter with lookup or current_skill if your caller cannot guarantee that.

If predicting for competitors you have never seen is the point rather than a mistake, say so once:

use trueskill_tt::{History, UnknownKeys};

let h = History::builder().unknown_keys(UnknownKeys::Prior).build();

An unknown competitor is then answered from the configured prior, which is the honest reading — you have no evidence about them — and correctly widens a team that contains one. There is deliberately no "skip the member" mode: a team's performance is the sum of its members, so dropping one would make the model more certain because it knows less.

Asking about one competitor

Gaussian answers tail questions directly, which is what a stopping rule needs:

use trueskill_tt::History;

let mut h = History::builder().build();
h.record_winner(&"alice", &"bob", 1).unwrap();
let _ = h.converge().unwrap();

let skill = h.current_skill(&"alice").unwrap();

// "How sure am I that this is below the cutoff?" — a probability, not a
// `mu + z * sigma` band whose confidence drifts as sigma changes.
let _ = skill.probability_below(20.0);

// Use this rather than `1.0 - probability_below(x)`: the complement cancels
// away every digit in the upper tail, which is where a stopping rule lives.
let _ = skill.probability_above(30.0);

Which match to play next

quality() measures whether a matchup is fair. That is not the same as whether it is informative, and the two only coincide for two evenly matched competitors. When each observation costs something, ask expected_information_gain instead — the outcome-weighted divergence between what you believe now and what you would believe afterwards.

use trueskill_tt::History;

let mut h = History::builder().build();
for t in 1..=10 {
    h.record_winner(&"veteran", &"regular", t).unwrap();
    h.record_winner(&"regular", &"veteran", t + 100).unwrap();
}
h.record_winner(&"veteran", &"newcomer", 500).unwrap();
h.converge().unwrap();

let settled = h.expected_information_gain(&[&[&"veteran"], &[&"regular"]]).unwrap();
let unknown = h.expected_information_gain(&[&[&"veteran"], &[&"newcomer"]]).unwrap();

// Playing the newcomer teaches you more than replaying a settled rivalry.
assert!(unknown > settled);

The result is in nats, and is bounded by the entropy of the outcome: at most ln 2 ≈ 0.693 for a two-way result, ln 3 once draws are possible, ln k for k outcomes. A value near zero means you already know how it ends.

This costs one full inference pass per possible outcome, so it is far more expensive than quality(). Scoring every pairing among n competitors is O(n² × outcomes) passes — shortlist with quality() or predict_win_probabilities first, then score only the shortlist.

Todo

  • Implement approx for Gaussian
  • Add more tests from TrueSkillThroughTime.jl
  • Generalise a time axis — Time is now a trait (Untimed, i64), not an enum
  • Add examples (examples/atp.rs, examples/scored.rs)
  • Add Observer (Observer / NullObserver)
  • Benchmark the inference loop (benches/batch.rs, benches/history_converge.rs, benches/ingest.rs)
  • N-team predict_outcome with draw mass, and expected_information_gain
  • Cross-check quality() against sublee/trueskill — N identical teams follow the closed form (1/5)^((n-1)/2) for the conventional parameters, asserted for n = 2..10, and the n=3/n=5 values (0.200, 0.040) match the reference package

License

Licensed under either of

at your option.

Contribution

Unless you explicitly state otherwise, any contribution intentionally submitted for inclusion in the work by you, as defined in the Apache-2.0 license, shall be dual licensed as above, without any additional terms or conditions.

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