ci: make the logout pending-state test deterministic (gate, not delay)
CI / web (push) Successful in 4m35s
CI / web (push) Successful in 4m35s
Same timing-window race as object-new-page: the 50ms delay let the logout resolve (menu unmounts on me=null) before findByText caught 'Signing out…' on the slow CI runner. Hold the logout open with a promise released only after the pending state is asserted. Co-Authored-By: Claude Opus 4.8 (1M context) <noreply@anthropic.com>
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@@ -1,7 +1,7 @@
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import { expect, test } from "vitest";
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import { screen, waitFor, within } from "@testing-library/react";
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import userEvent from "@testing-library/user-event";
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import { delay, http, HttpResponse } from "msw";
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import { http, HttpResponse } from "msw";
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import { server } from "../test/server";
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import { renderApp } from "../test/render";
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import { UserMenu } from "./user-menu";
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@@ -35,9 +35,13 @@ test("opens the menu showing email + role and signs out", async () => {
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});
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test("shows a pending state on Sign out while logging out", async () => {
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let release!: () => void;
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const gate = new Promise<void>((resolve) => {
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release = resolve;
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});
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server.use(
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http.post("/api/admin/logout", async () => {
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await delay(50);
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await gate;
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return new HttpResponse(null, { status: 204 });
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}),
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);
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@@ -50,5 +54,10 @@ test("shows a pending state on Sign out while logging out", async () => {
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const menu = within(document.body);
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await userEvent.click(await menu.findByText("Sign out"));
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// The logout is held open by `gate`, so the pending state is observed
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// deterministically (no reliance on a timing window).
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expect(await menu.findByText(/signing out/i)).toBeInTheDocument();
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release();
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await waitFor(() => expect(menu.queryByText(/signing out/i)).toBeNull());
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});
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