Files
trueskill-tt/tests/key_ergonomics.rs
T
logaritmiskandClaude Opus 5 e72bf3894c refactor!: the joint is reached through Joint, not mirrored on History
`posterior_of`, `posterior_of_at` and `expected_variance_reduction`
existed twice: once on `Joint`, and once on `History` as one-shot
wrappers whose whole body was `self.joint()?.<same>(..)`.

The wrappers re-factorised on every call — their own docs said so,
warning the reader to take a `Joint` instead — and they were what
smuggled the scored-only precondition onto the flat surface. A user
following the quickstart builds a ranked history, sees `posterior_of` in
the method list, and it never works. `h.joint()?.posterior_of(..)` is
one call longer and tells the truth: you need a joint, and a joint needs
a scored history.

That leaves three tiers instead of a flat surface with a hidden
precondition: `History` fits and reads, `predict_*` forecasts, `Joint`
answers exact joint questions.

`predict_margin` was itself calling `self.posterior_of`; it goes through
`self.joint()?` directly now.

The `Joint` methods' docs referred back to the wrappers for their real
content ("Identical to `History::posterior_of`, without re-paying the
factorisation"), so they now carry it: what a linear functional means,
which appearance each competitor is read at, and why
`expected_variance_reduction` belongs on the handle.

`tests/joint_handle.rs` had three tests comparing the wrapper against
the handle. That comparison is gone, but the property behind it is not —
they now compare a *reused* joint against a *fresh* one per question,
which is the actual correctness claim behind caching the factorisation
(#51), without the wrapper in the middle.

Closes #78.

Co-Authored-By: Claude Opus 5 (1M context) <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_011hcFjNDmHXZF8URGLku5zZ
2026-09-10 06:40:31 +02:00

128 lines
4.2 KiB
Rust

//! The realistic program: keys arrive owned, queries are written with literals.
//!
//! Every prediction and joint query used to take `&[&[&K]]`, which at
//! `K = String` made a string literal *impossible* — the shape required three
//! levels of temporaries that all had to outlive the call. They are generic
//! over the borrowed key now, so one spelling works at both key types.
//!
//! Both key types are exercised in every test, because the point is that the
//! spelling is the same.
use trueskill_tt::{ConstantDrift, History, NullObserver};
type Owned = History<i64, ConstantDrift, NullObserver, String>;
type Borrowed = History<i64, ConstantDrift, NullObserver, &'static str>;
fn owned() -> Owned {
let mut h: Owned = History::builder().key_type::<String>().build();
for t in 1..=4 {
h.record_winner(&"alice".to_string(), &"bob".to_string(), t)
.expect("ingests");
}
h.converge().expect("converges");
h
}
fn borrowed() -> Borrowed {
let mut h = History::default();
for t in 1..=4 {
h.record_winner(&"alice", &"bob", t).expect("ingests");
}
h.converge().expect("converges");
h
}
#[test]
fn predictions_take_literals_at_either_key_type() {
let teams: &[&[&str]] = &[&["alice"], &["bob"]];
let a = owned()
.predict_win_probabilities(teams)
.expect("K = String");
let b = borrowed()
.predict_win_probabilities(teams)
.expect("K = &'static str");
assert_eq!(a, b, "the same fit through the same spelling");
assert!(a[0] > a[1], "alice won every game");
}
#[test]
fn every_team_shaped_query_accepts_the_same_slice() {
let h = owned();
let teams: &[&[&str]] = &[&["alice"], &["bob"]];
h.quality(teams).expect("quality");
let _ = h.predict_outcome(teams).expect("outcome");
h.predict_ranking(teams, &[0, 1]).expect("ranking");
h.expected_information_gain(teams)
.expect("information gain");
}
#[test]
fn linear_combinations_take_bare_keys() {
// `&[(&K, f64)]` at `K = String` meant `&[(&String, f64)]` — no literals.
// A scored history, because the joint needs one.
let mut h: Owned = History::builder().key_type::<String>().build();
for t in 1..=4 {
h.event(t)
.team([String::from("alice")])
.team([String::from("bob")])
.scores([21.0, 9.0])
.commit()
.expect("ingests");
}
h.converge().expect("converges");
let terms: &[(&str, f64)] = &[("alice", 1.0), ("bob", -1.0)];
let gap = h
.joint()
.expect("scored history has a joint")
.posterior_of(terms)
.expect("both keys are known");
assert!(gap.mu() > 0.0, "alice outscored bob every round");
}
/// `lookup` is gone with `Index` (#73); the accessors that answer the same
/// question all take a borrowed key.
#[test]
fn membership_queries_accept_a_borrowed_key() {
let h = owned();
assert!(h.current_skill("alice").is_some());
assert!(h.rating("alice").is_some());
assert!(h.learning_curve("alice").is_some());
assert!(h.current_skill("nobody").is_none());
assert!(h.rating("nobody").is_none());
assert!(h.learning_curve("nobody").is_none());
}
#[test]
fn gamma_sets_drift_without_naming_constant_drift() {
let mut a: Borrowed = History::builder().gamma(0.5).build();
let mut b: Borrowed = History::builder().drift(ConstantDrift::new(0.5)).build();
for h in [&mut a, &mut b] {
h.record_winner(&"x", &"y", 1).unwrap();
h.record_winner(&"y", &"x", 100).unwrap();
h.converge().unwrap();
}
let (ga, gb) = (a.current_skill("x").unwrap(), b.current_skill("x").unwrap());
assert_eq!((ga.mu(), ga.sigma()), (gb.mu(), gb.sigma()));
// Control: the shorthand is not a no-op — a different gamma differs.
let mut c: Borrowed = History::builder().gamma(0.0).build();
c.record_winner(&"x", &"y", 1).unwrap();
c.record_winner(&"y", &"x", 100).unwrap();
c.converge().unwrap();
assert_ne!(c.current_skill("x").unwrap().sigma(), ga.sigma());
}
#[test]
#[should_panic(expected = "gamma must be finite and non-negative")]
fn a_negative_gamma_is_rejected_rather_than_squared_away() {
let _: Borrowed = History::builder().gamma(-0.5).build();
}