Files
trueskill-tt/src/acquisition.rs
T
logaritmiskandClaude Opus 5 17d072b2ae fix: route every transcendental through libm, and combine sigmas with hypot
Follow-on from #41, which added `libm` for `erfc`. Surveying what else
the dependency offers: its unique surface over `std` is `erf`/`erfc`,
`lgamma`/`tgamma` and Bessel functions, and only the first was ever
needed. But the survey found something better than another special
function.

`std`'s `exp` and `ln` delegate to the *system* math library. IEEE 754
specifies the basic operations and `sqrt` exactly and says nothing about
transcendentals, so those differ per platform. Measured here over 200k
inputs:

    exp: 19425/200000 differ from libm (worst 1 ulp)
    log:  9932/200000 differ

Inference is an iterative fixed point, so a one-ULP difference can change
an iteration count and move the answer by more than one ULP. Routing
every transcendental through `libm` makes a fit reproducible across
platforms — a stronger guarantee than `tests/determinism.rs`, which only
covers thread counts.

It costs nothing. `Batch::iteration` measured -2.7% [-5.7%, -0.3%] with
the whole set swapped, and not one golden moved.

Also switches the two places that combined sigmas as
`sqrt(a^2 + b^2)` to `hypot`. Squaring overflows to infinity above
~1.3e154 and flushes to zero below ~1.5e-154 — measured, the naive form
returns `inf` where `hypot` returns 1.41e160 — and `Gaussian`'s
constructors are public, so a caller can reach both ends.

Deliberately not done: rewriting the KL divergence's `ln` of a ratio via
`ln_1p`. The cancellation is real as the ratio approaches one, but
measured absolute error is at most ~1e-11 in a quantity of order 0.4
nats, so it changes nothing.

The invariant is recorded in `CLAUDE.md` and on `erfc`'s own docs, since
nothing enforces it mechanically.

Co-Authored-By: Claude Opus 5 (1M context) <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_011hcFjNDmHXZF8URGLku5zZ
2026-09-07 22:33:30 +02:00

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//! Active learning: which comparison teaches you the most.
//!
//! [`quality`](crate::quality) answers "is this matchup *fair*". That is a
//! different question from "is this matchup *informative*", and the two
//! coincide only for two evenly matched competitors. When each observation
//! costs something — a human click, a scheduled fixture — the question worth
//! asking is the second one.
//!
//! The quantity here is expected information gain: the outcome-weighted
//! divergence between what you believe now and what you would believe after
//! seeing the result.
//!
//! ```text
//! EIG(matchup) = SUM P(outcome) * KL( posterior_after(outcome) || prior )
//! outcome
//! ```
//!
//! It is the mutual information between the observed outcome and the skills,
//! which is worth remembering because it pins the scale: information gain
//! cannot exceed the entropy of the thing you are about to observe. A contest
//! with `k` distinguishable outcomes can teach you at most `ln k` nats,
//! whatever the ratings. That ceiling is the sharpest available test of an
//! implementation — see [`expected_information_gain`].
use crate::{
GameOptions, Gaussian, InferenceError, Outcome, Rating, drift::Drift, predict, time::Time,
};
/// Outcomes below this probability contribute nothing measurable and are not
/// worth an inference pass.
///
/// The contribution of an outcome is `P * KL`, and `KL` is bounded in practice
/// by tens of nats, so a probability this small moves the total by less than
/// the quadrature error already present in `P` itself.
const NEGLIGIBLE: f64 = 1e-12;
/// `KL(q || p)` for two univariate Gaussians, in nats.
///
/// Both arguments are proper posteriors from inference, so the degenerate
/// cases guarded here (zero or infinite variance) indicate that inference has
/// broken down rather than anything a caller did.
fn kl_divergence(q: Gaussian, p: Gaussian) -> f64 {
let (var_q, var_p) = (q.sigma().powi(2), p.sigma().powi(2));
if !(var_q.is_finite() && var_p.is_finite()) || var_q <= 0.0 || var_p <= 0.0 {
return 0.0;
}
let mean_gap = q.mu() - p.mu();
0.5 * (libm::log(var_p / var_q) + (var_q + mean_gap * mean_gap) / var_p - 1.0)
}
/// Expected information gain of a hypothetical matchup, in nats.
///
/// Enumerates the outcomes this matchup could have, runs inference for each to
/// get the belief it would produce, and weights the resulting divergence by
/// that outcome's probability. A higher value means the result would teach you
/// more.
///
/// # Interpreting the value
///
/// Nats. The upper bound is the entropy of the outcome variable: at most
/// `ln 2 ≈ 0.693` for a two-way result, `ln 3 ≈ 1.099` once draws are
/// possible, `ln k` for `k` outcomes. A value near the ceiling means the
/// result is close to a coin flip *and* would move the posteriors a long way;
/// a value near zero means you already know what will happen, or that the
/// result would barely change your beliefs if you saw it.
///
/// This is not a monotone transform of [`quality`](crate::quality). A lopsided
/// matchup between two uncertain competitors scores well on quality-times-
/// variance heuristics and poorly here, because the near-certain outcome
/// carries almost no information.
///
/// # Cost
///
/// One full inference pass per possible outcome, so this is far more expensive
/// than `quality()` — which is one closed-form evaluation. The outcome count
/// grows quickly with team count (3 outcomes for two teams that can draw, 13
/// for three, 75 for four), and scoring every candidate pairing among `n`
/// competitors is `O(n² × outcomes)` inference passes.
///
/// For a selector over many candidates, shortlist with the cheap
/// [`quality`](crate::quality) or
/// [`predict_win_probabilities`](crate::History::predict_win_probabilities)
/// first and score only the shortlist here. The expected-variance-reduction
/// proxy sometimes suggested as a cheaper alternative is *not* cheaper: it
/// needs the same hypothetical posteriors, so it shares the dominant cost.
///
/// # Errors
///
/// - `NotEnoughTeams` if fewer than two teams are supplied.
/// - `EmptyTeam` if any team has no members.
/// - `TooManyTeams` if the outcome space is too large to enumerate; see
/// [`MAX_PREDICTED_TEAMS`](crate::MAX_PREDICTED_TEAMS).
/// - `InvalidProbability` if `options.p_draw` is outside `[0.0, 1.0)`.
/// - Anything [`Game::ranked`](crate::Game::ranked) returns for a hypothetical
/// outcome.
pub fn expected_information_gain<T: Time, D: Drift<T>>(
teams: &[&[Rating<T, D>]],
options: &GameOptions,
) -> Result<f64, InferenceError> {
if teams.len() < 2 {
return Err(InferenceError::NotEnoughTeams { got: teams.len() });
}
if teams.len() > crate::MAX_PREDICTED_TEAMS {
return Err(InferenceError::TooManyTeams {
got: teams.len(),
max: crate::MAX_PREDICTED_TEAMS,
});
}
if !(0.0..1.0).contains(&options.p_draw) {
return Err(InferenceError::InvalidProbability {
value: options.p_draw,
});
}
for (idx, team) in teams.iter().enumerate() {
if team.is_empty() {
return Err(InferenceError::EmptyTeam { team: idx });
}
}
// Prediction runs on performances: skill inflated by each member's beta.
let performances: Vec<Gaussian> = teams
.iter()
.map(|team| {
team.iter()
.fold(crate::N00, |acc, rating| acc + rating.performance())
})
.collect();
// Draw margins per pair, derived from the teams' betas exactly as
// inference derives them, so the outcomes weighted here are the outcomes
// that would actually be fitted.
let beta_sq: Vec<f64> = teams
.iter()
.map(|team| team.iter().map(|r| r.beta().powi(2)).sum())
.collect();
let p_draw = options.p_draw;
let margins = predict::Margins::new(teams.len(), |i, j| {
if p_draw == 0.0 {
0.0
} else {
crate::compute_margin(p_draw, (beta_sq[i] + beta_sq[j]).sqrt())
}
});
let mut gain = 0.0;
for (ranks, probability) in predict::outcome_distribution(&performances, &margins) {
if probability <= NEGLIGIBLE {
continue;
}
let game = crate::Game::ranked(teams, Outcome::ranking(ranks), options)?;
let posteriors = game.posteriors();
// Beliefs factorise across competitors, so the joint divergence is the
// sum of the per-competitor ones.
let divergence: f64 = teams
.iter()
.zip(&posteriors)
.flat_map(|(team, posterior)| team.iter().zip(posterior))
.map(|(rating, &after)| kl_divergence(after, rating.prior()))
.sum();
gain += probability * divergence;
}
Ok(gain)
}
#[cfg(test)]
mod tests {
use super::*;
use crate::{BETA, ConstantDrift, GAMMA};
type R = Rating<i64, ConstantDrift>;
fn rating(mu: f64, sigma: f64) -> R {
R::new(Gaussian::from_ms(mu, sigma), BETA, ConstantDrift(GAMMA))
}
fn options(p_draw: f64) -> GameOptions {
GameOptions {
p_draw,
..GameOptions::default()
}
}
fn eig(teams: &[&[R]], p_draw: f64) -> f64 {
expected_information_gain(teams, &options(p_draw)).unwrap()
}
/// The analytic ceiling. Information gain is the mutual information between
/// the outcome and the skills, so it cannot exceed the entropy of the
/// outcome variable — whatever the ratings. This is the check a subtly
/// wrong implementation fails while still returning plausible numbers: an
/// early prototype of this returned 4.77 nats from a sign error and passed
/// every monotonicity test.
#[test]
fn never_exceeds_the_entropy_of_the_outcome() {
let ceiling_two = std::f64::consts::LN_2;
for (a, b) in [
(rating(0.0, 6.0), rating(0.0, 6.0)),
(rating(0.0, 0.5), rating(0.0, 0.5)),
(rating(12.0, 6.0), rating(-12.0, 6.0)),
(rating(40.0, 1.0), rating(-40.0, 1.0)),
(rating(3.0, 6.0), rating(-2.0, 0.1)),
(rating(0.0, 25.0), rating(0.0, 25.0)),
] {
let g = eig(&[&[a], &[b]], 0.0);
assert!(
g >= 0.0 && g <= ceiling_two,
"EIG {g} outside [0, ln 2] for mu=({}, {}) sigma=({}, {})",
a.prior().mu(),
b.prior().mu(),
a.prior().sigma(),
b.prior().sigma()
);
}
}
/// With draws enabled there are three outcomes, so the ceiling rises to
/// `ln 3` — and the two-outcome bound no longer applies.
#[test]
fn the_ceiling_follows_the_outcome_count() {
let ceiling_three = 3.0f64.ln();
for sigma in [0.5, 3.0, 6.0, 25.0] {
let g = eig(&[&[rating(0.0, sigma)], &[rating(0.0, sigma)]], 0.25);
assert!(
g >= 0.0 && g <= ceiling_three,
"EIG {g} outside [0, ln 3] at sigma {sigma}"
);
}
}
/// An even matchup between uncertain competitors is the informative one.
/// A hopelessly lopsided matchup teaches you almost nothing, because you
/// already know how it ends.
#[test]
fn an_even_matchup_beats_a_lopsided_one() {
let even = eig(&[&[rating(0.0, 6.0)], &[rating(0.0, 6.0)]], 0.0);
let lopsided = eig(&[&[rating(12.0, 6.0)], &[rating(-12.0, 6.0)]], 0.0);
assert!(
even > lopsided,
"even {even} should beat lopsided {lopsided}"
);
}
/// Certainty is the thing information gain is measuring the absence of:
/// the less you know, the more there is to learn.
#[test]
fn gain_falls_as_certainty_rises() {
let mut previous = f64::INFINITY;
for sigma in [12.0, 6.0, 3.0, 1.0, 0.5, 0.1] {
let g = eig(&[&[rating(0.0, sigma)], &[rating(0.0, sigma)]], 0.0);
assert!(
g < previous,
"sigma {sigma}: {g} did not fall below {previous}"
);
previous = g;
}
assert!(previous >= 0.0);
}
/// The heuristic this replaces is `quality * sigma_a^2 * sigma_b^2`. It is
/// not a monotone transform of information gain — it ranks a lopsided
/// matchup above a confident even one, and EIG ranks them the other way.
/// Pinning the disagreement down is what stops a future "simplification"
/// from quietly reverting to the heuristic.
#[test]
fn disagrees_with_the_quality_times_variance_heuristic() {
let heuristic = |a: &R, b: &R| {
crate::quality(&[&[a.prior()], &[b.prior()]], BETA)
* a.prior().sigma().powi(2)
* b.prior().sigma().powi(2)
};
let (confident_a, confident_b) = (rating(0.0, 0.5), rating(0.0, 0.5));
let (lopsided_a, lopsided_b) = (rating(12.0, 6.0), rating(-12.0, 6.0));
assert!(
heuristic(&lopsided_a, &lopsided_b) > heuristic(&confident_a, &confident_b),
"the heuristic should prefer the lopsided matchup"
);
assert!(
eig(&[&[confident_a], &[confident_b]], 0.0) > eig(&[&[lopsided_a], &[lopsided_b]], 0.0),
"information gain should prefer the even matchup"
);
}
#[test]
fn supports_more_than_two_teams() {
let teams: Vec<Vec<R>> = vec![
vec![rating(0.0, 6.0)],
vec![rating(0.0, 6.0)],
vec![rating(0.0, 6.0)],
];
let refs: Vec<&[R]> = teams.iter().map(Vec::as_slice).collect();
let g = expected_information_gain(&refs, &options(0.0)).unwrap();
// Six distinguishable orderings with no draws.
assert!(
g > 0.0 && g <= 6.0f64.ln(),
"three-team EIG {g} out of range"
);
}
#[test]
fn multi_member_teams_are_supported() {
let a = [rating(0.0, 6.0), rating(1.0, 4.0)];
let b = [rating(0.0, 6.0)];
let g = expected_information_gain(&[&a, &b], &options(0.0)).unwrap();
assert!(g > 0.0 && g <= std::f64::consts::LN_2, "{g}");
}
#[test]
fn degenerate_shapes_are_errors() {
let a = [rating(0.0, 6.0)];
assert!(matches!(
expected_information_gain(&[&a], &options(0.0)),
Err(InferenceError::NotEnoughTeams { got: 1 })
));
let empty: [R; 0] = [];
assert!(matches!(
expected_information_gain(&[&a, &empty], &options(0.0)),
Err(InferenceError::EmptyTeam { team: 1 })
));
assert!(matches!(
expected_information_gain(&[&a, &a], &options(1.5)),
Err(InferenceError::InvalidProbability { .. })
));
}
#[test]
fn kl_divergence_is_zero_for_identical_beliefs() {
let g = Gaussian::from_ms(3.0, 2.0);
assert!(kl_divergence(g, g).abs() < 1e-15);
}
#[test]
fn kl_divergence_is_non_negative_and_grows_with_separation() {
let prior = Gaussian::from_ms(0.0, 3.0);
let mut previous = 0.0;
for mu in [0.0, 0.5, 1.0, 2.0, 4.0] {
let d = kl_divergence(Gaussian::from_ms(mu, 3.0), prior);
assert!(d >= 0.0, "negative divergence at mu {mu}: {d}");
assert!(d >= previous, "not increasing at mu {mu}");
previous = d;
}
}
}